A function g(x) is discontinuous at x = p if the one-sided limits (from the left and from the right) are different.
For the given function g, we see that:
[tex]\begin{gathered} \lim _{x\to-2^-}g(x)=-1 \\ \\ \lim _{x\to-2^{^+}}g(x)=-3 \end{gathered}[/tex]
So, this function has a discontinuity at x = -2.
Now, for x = 1, we see that both side limits are infinity. So, they are the same. Thus, this function does not have a discontinuity at this point.
Therefore, the answer is -2
