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An inclined plane makes an angle of 30 degrees above the horizontal. If a block of 7 kg rests on the incline, what is the magnitude of the normal force that the incline exerts on the block?

An inclined plane makes an angle of 30 degrees above the horizontal If a block of 7 kg rests on the incline what is the magnitude of the normal force that the i class=

Respuesta :

Given data

*The given mass of the block is m = 7 kg

*The given angle is

[tex]\theta=30^0[/tex]

The formula for the magnitude of the normal force that the inclined plane exerts on the block is given as

[tex]f_n=mg\cos \theta[/tex]

Substitute the known values in the above expression as

[tex]\begin{gathered} f_n=(7)(9.8)\cos 30^0 \\ =59.41\text{ N} \end{gathered}[/tex]

Hence, the magnitude of the normal force that the inclined plane exerts on the block is F_n = 59.41 N

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