The line passes through (-6,-3) and (4,-3)
Its slope is:
[tex]\frac{-3-(-3)}{4-(-6)}=0[/tex]
Then, the point slope form of the equation is:
y - (-3) = 0[x - (-6)]
y + 3 = 0(x + 6)
y + 3 = 0
Therefore, the slope-intercept form is y = -3
In function notation, we have: f(x) = -3
