Using SOHCAHTOA principle
[tex]\begin{gathered} tan17=\frac{opposite}{\text{adjacent}} \\ \text{opposite = x} \\ \text{adjacent }=8.6ft \\ tan17=\frac{x}{8.6} \\ \text{cross multiply} \\ tan17\times8.6=x \\ x=3.49391564547\times8.6 \\ x=30.0476745511 \\ x\approx30.0ft \end{gathered}[/tex]
