Respuesta :

let assume a number x

According to question Twice a number is more than the sum of that number and 14

So we can write it as:

[tex]2x>x+14[/tex]

Solving the above ineqaulity:

[tex]\begin{gathered} 2x>x+14 \\ 2x-x>x-x+14 \\ x>14 \end{gathered}[/tex]

So the number should be greater than 14.

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