[tex]\begin{gathered} 3x^2-2x=4\Rightarrow3x^2-2x-4=0 \\ 3x^2-2x-4=0 \\ We\text{ cannot factorize so we will use the quadratic formula} \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ a=3,b=-2,c=-4 \\ \text{Plug that into the equation, we have:} \\ x=\frac{-(-2)_{}\pm\sqrt[]{(-2^2)-4(3)(-4)}}{2(3)} \\ x=\frac{2\pm\sqrt[]{4+48}}{6} \\ x=1.535183758488,-0.86851709182133 \\ x\approx1.54,-0.87 \end{gathered}[/tex]