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What is the equation of the line that has a slope of 4 and passes through the point (4,8)?OA. y + 8 = −4(x + 4)OB. y + 4 = -4(x - 8)OC. y - 4 = 4(x + 8)OD. y - 8 = 4(x-4)

Respuesta :

Answer:

The correct answer is the option D. y - 8 = 4(x - 4)

Explanation:

Given a point and the slope, we can write the equation of the line as:

[tex]\begin{gathered} P=(x_0,y_0) \\ y-y_0=m(x-x_0) \end{gathered}[/tex]

Where, P is the point given and m is the slope. In this case, P = (4 , 8) and m = 4

Thus,

[tex]y-8=4(x-4)[/tex]

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