Let:
n = Number of solid chocolates = 8
N = Total number of chocolates = 28
[tex]\begin{gathered} 1st_{\text{ }}case\colon \\ \frac{n}{N}=\frac{8}{28}=\frac{2}{7} \\ 2nd_{\text{ }}case\colon \\ \frac{n-1}{N-1}=\frac{7}{27} \end{gathered}[/tex]So, the probability of selecting 2 solid chocolates in a row are:
[tex]\frac{2}{7}\cdot\frac{7}{27}=0.074[/tex]Answer:
7.4%
