There are 180 students in a school band attending an awards dinner. A random survey of 20 band students was conducted to determine how many of each meal should be prepared for the dinner. The results of the survey are shown. 11 students selected Cajun pasta. 4 students selected chicken pasta. 5 students selected shrimp pasta. Based on the survey results, which of these is the best prediction of the meals wanted by the 180 students?1. There are 22 students who want chicken pasta than shrimp pasta 2. There are 60 students who want either chicken pasta or shrimp pasta3. There are 36 students who want Cajun pasta

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ZackaryI34915 ZackaryI34915 · Answer 1 · 2022-10-30T04:03:53+01:00

We can extrapolate the survey, of sample size n=20, results to the population (180 students).

To do that we have to multiply the frequency of the survey by 180/20=9.

Then, we can expect:

11 * 9 = 99 will select Cajun pasta.

4 * 9 = 36 will select chicken pasta.

5 * 9 = 45 will select shrimp pasta.

Then, we can evaluate each option:

1. There are 22 students who want chicken pasta than shrimp pasta:

There are 36 students that prefer chicken pasta rather than the other options, so this is not correct.

2. There are 60 students who want either chicken pasta or shrimp pasta.

There are 36+45=81 students who want either chicken pasta or shrimp pasta, so this is not correct.

3. There are 36 students who want Cajun pasta.