[tex]2x^2-1>6x[/tex]
Solve for x:
[tex]\begin{gathered} 2x(x-3)>1 \\ so: \\ x>\frac{1}{2}(3+\sqrt{11})\approx3.158 \\ or \\ x<\frac{1}{2}(3-\sqrt{11})\approx-0.158 \end{gathered}[/tex]
Therefore, the correct options will be:
[tex]\begin{gathered} x=5 \\ x=-4 \\ x=-2 \end{gathered}[/tex]
