Solution:
Given:
[tex]\begin{gathered} r=4m \\ \theta=\frac{3\pi}{4}radians \end{gathered}[/tex]The length of an arc is given by;
[tex]\begin{gathered} l=r\theta \\ l=4\times\frac{3\pi}{4} \\ l=3\pi \\ l=9.42477796077 \\ \\ To\text{ the nearest tenth,} \\ l\approx9.4m \end{gathered}[/tex]Therefore, to the nearest tenth, the length of the arc is 9.4m
