For
[tex]2x^2+7x-5=0[/tex]Using the quadratic formula we get:
[tex]\frac{-7\pm\sqrt[]{7^2-4\cdot2\cdot(-5)}}{2\cdot2}[/tex][tex]\frac{-7\pm\sqrt[]{49^{}+40}}{4}[/tex][tex]\frac{-7\pm\sqrt[]{89}}{4}[/tex]So the solutions are:
[tex]x=\frac{-7+\sqrt[]{89}}{4}[/tex]And
[tex]x=\frac{-7-\sqrt[]{89}}{4}[/tex]