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find all solutions of the equation [tex] {x}^{2} + 2x + 5 = 0[/tex]first input the solution with b < 0 here: the real number a equals ______and the real number b equals ______the input the solution with b > 0 here:the real number a equals ______and the real number b equals ______

Respuesta :

Problem

Solution

For this case we cna use the quadratic formula given by:

[tex]x=\frac{-b+\sqrt[]{b^2-4ac}}{2a}[/tex]

Where a= 1, b= 2, c=5. Replacing we got:

[tex]x=\frac{-2-\sqrt[]{4-4(1)(5)}}{2(1)}=\frac{-2-\sqrt[]{-16}}{2}=-1-2i[/tex][tex]x=\frac{-2+\sqrt[]{4-4(1)(5)}}{2(1)}=\frac{-2+\sqrt[]{-16}}{2}=-1+2i[/tex]

And then the solution would be:

When b<0

a= -1

b= -2

When b>0

a= -1

b= 2

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