Given the function
[tex]f(x)=x^2-5x[/tex]
For f(x) < 0, we have:
[tex]x^2-5x<0[/tex]
And solve for x by factor:
[tex]x(x-5)<0[/tex]
Separate the solutions:
[tex]\begin{gathered} x>0 \\ and \\ x-5<0 \\ x-5+5<0+5 \\ x<5 \end{gathered}[/tex]
The values for x in inequality form:
[tex]0Or in interval notation:[tex](0,5)[/tex]
Answer:
values of x: 0 < x < 5
