f(x)= 3(0.5)^x
We will substitute the values of x the domain in the function to obtain the range
[tex]\begin{gathered} \text{when x = 0}^{} \\ y=3(0.5)^0=\text{ 3 x (}\frac{1}{2})^0=3\text{ x 1 = 3} \\ \\ \text{when x = }1 \\ y=3(0.5)^1\text{ = 3 x (}\frac{1}{2})^1=\frac{3}{2} \\ \\ \end{gathered}[/tex][tex]\begin{gathered} \text{when x = 2} \\ y\text{ = 3 x (}\frac{1}{2})^{2\text{ }}=\text{ }\frac{3}{4} \end{gathered}[/tex]
