To get the value of y, we will apply the trigonometeric ratio
From the image given,
Opposite side = y
hypotenuse = 6
so we can then use the relation:
[tex]\sin \emptyset=\frac{opposite}{hypotenuse}[/tex]
[tex]\emptyset=45^0[/tex]
[tex]\sin 45=\frac{y}{6}[/tex]
[tex]y=6\sin 45^0[/tex][tex]y=6\text{ x}\frac{\sqrt[]{2}}{2}=3\sqrt[]{2}[/tex]
The answer is 3 square root of 2
