what is the average rate of change in elevation for the road over the first 4km? remember that f(x) stands for hundreds of feet. include units in your answer.

Respuesta :

Answer:

3 hundred ft / km

Explanation:

The average rate of change for a function is

[tex]\frac{f(a)-f(b)}{a-b}[/tex]

in our case this is

[tex]\begin{gathered} \frac{f(4)-f(0)}{4-0} \\ \end{gathered}[/tex]

now

f(4) = 19 hundred ft

f(0) = 7 hundred ft

therefore,

[tex]\frac{19-7}{4-0}[/tex][tex]=3(\text{hundred ft/km)}[/tex]

which is our answer!