ANSWER :
x > 2
EXPLANATION :
From the problem, we have the inequality :
[tex]3<4x-5[/tex]
Solve for x :
Put the terms with variables on the left side and the constants to the right side.
Subtract 4x from both sides :
[tex]\begin{gathered} 3-4x<\cancel{4x}-5-\cancel{4x} \\ 3-4x<-5 \end{gathered}[/tex]
Subtract 3 from both sides :
[tex]\begin{gathered} \cancel{3}-4x-\cancel{3}<-5-3 \\ -4x<-8 \end{gathered}[/tex]
Divide both sides by -4.
Take note that if you divide a negative number from the inequality, the symbol will change.
So from "<", it will become ">"
[tex]\begin{gathered} \frac{\cancel{-4}x}{\cancel{-4}}<\frac{-8}{-4} \\ x>2 \end{gathered}[/tex]
The solution is x > 2
The graph will be :
The boundary line is a dashed type since the symbol is ">" and the region is to the right of x = 2
