SOLUTION:
Step 1:
We are to find an appropriate expresson for the range for the number of Chirps.
Step 2;
The equation given is y = 5x - 30
The range of x given;
[tex]-30\text{ }\leq\text{ x }\leq\text{ 44}[/tex]Step 3:
We substitute both the lowest and greatest value into the equations;
[tex]\begin{gathered} y\text{ = 5x -30} \\ \text{when x = -30} \\ y\text{ = 5 (-30) - 30} \\ y\text{ = -150 - 30} \\ y\text{ = -180} \end{gathered}[/tex][tex]\begin{gathered} y\text{ = 5x - 30} \\ \text{when x = 44} \\ y\text{ = 5 (44) - 30} \\ y\text{ = 220 - 30} \\ y\text{ = 190} \end{gathered}[/tex]Step 4:
It is very obvious that the number of Chirps can never be negative so we need to ignore the -180 and set our range to start from zero.
We now have;
[tex]0\text{ }\leq\text{ y }\leq\text{ 190}[/tex]