A sample of gas in a rigid steel tank is under 157.9 kPa of pressure at 317 Kelvins.If the tank is heated to 358 Kelvins, what would the new pressure be in kilopascals?178144160210

Respuesta :

Answer:

178kPa

Explanations

According to Gay Lussac's law, the pressure of a given gas is directly proportional to temperature provided that the volume is constant.

[tex]\begin{gathered} P=kT \\ k=\frac{P_1}{T_1}=\frac{P_2}{T_2} \end{gathered}[/tex]

Given the following parameters

Initial pressure P1 = 157.9kPa

Initial temperature T1 = 317K

Final temperature T2 = 358K

Required

New pressure P2

Substitute

[tex]\begin{gathered} P_2=\frac{P_1T_2}{T_1} \\ P_2=\frac{157.9\times358}{317} \\ P_2=\frac{56528.2}{317} \\ P_2\approx178kPa \end{gathered}[/tex]

Hence the new pressure in kPa is 178kPa