7A painted design on a tile is composedof a square and two right triangles. Eachside of the square and the height of eachtriangle measure 4.5 inches. The base ofeach triangle measures 6 inches.What is the total area of the painteddesign in square inches?10212(3 (3)4400100OOO212(3 (3)(414 (4)515 (5 56 (6 (6) 6W0100(8)818 (8) (8)919 ( (9 9©(8)8(9

7A painted design on a tile is composedof a square and two right triangles Eachside of the square and the height of eachtriangle measure 45 inches The base ofea class=

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There are two different shapes in the iamge, the first is a rectangle and the second is a triangle. To determine the area of each of these, we need to use the following expressions:

[tex]\begin{gathered} A_{\text{square}}=side^2 \\ A_{triangle}=\frac{b\cdot h}{2} \end{gathered}[/tex]

Since there are two triangles, the total area of the image is:

[tex]A=A_{\text{square}}+2\cdot A_{\text{triangle}}[/tex]

So we need to calculate the area of each shape first. This is done below:

[tex]\begin{gathered} A_{\text{square}}=4.5^2=20.25\text{ square inches} \\ A_{\text{triangle}}=\frac{4.5\cdot6}{2}=13.5\text{ square inches} \end{gathered}[/tex]

Now we can calculate the total area:

[tex]A=20.25+2\cdot13.5=47.25\text{ square inches}[/tex]

The total area is 47.25 square inches