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Use the position function s(t) = –4.9t^2 + 700, which gives the height (in meters) of an object that has fallen for t seconds from a height of 700 meters. The velocity at time t = a seconds is given by the following.

Use the position function st 49t2 700 which gives the height in meters of an object that has fallen for t seconds from a height of 700 meters The velocity at ti class=

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Answer:

Explanation:

Here, we want to get the velocity at time t

To do this, we have to find the first derivative of the given position function

Mathematically, we have that as:

[tex]S^{\prime}(t)\text{ = 2(-4.9)(t) = -9.8t}[/tex]

We simply proceed to substitute the value of t = 5 seconds

We have this as:

[tex]undefined[/tex]

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