Here given that
[tex](x-\frac{2}{3})(x+\frac{9}{3})[/tex]
Further simplification we have to take lcm first
[tex](\frac{3x}{3}-\frac{2}{3})(\frac{3x}{3}+\frac{9}{3})=\frac{(3x-2)}{3}\times\frac{(3x+9)}{3}=\frac{(3x-2)(3x+9)}{9}[/tex]
Also
So finally we get the factors are
[tex](3x-2)(3x+9)[/tex]
