contestada

1 point You are testing two different fertilizers on identical plants A and B. Plant Als 6 inches tall and growing at a rate of 4 inches per day. Plant Bis 10 inches call and growing at a rate of 2 inches per day. How would you write the equations? y = 4 +63 Y = 2 + 10.2 2 y=4 – 62 y = 2 – 10.2 Y = = 42 + 6 y = 2x + 10 y = – 42+6 y = -2x + 10

Respuesta :

We have to find the equation that relate height y with time x.

In the case of Plant A, it starts with a height of 6 inches, so y(0)=6. It grows 4 inches per day, so we will have:

[tex]\frac{y(1)-y(0)}{1-0}=4=\text{slope m}[/tex]

Then, as the slope is constant, we have a linear function, with y-intercept b=y(0)=6 and slope m=4, which equation can be written as:

[tex]y=4x+6[/tex]

If we apply the same analysis to plant B, we have that the y-intercept is y(0)=10 and the slope is m=2 inches per day.

Then, the equation for B is:

[tex]y=2x+10[/tex]

Answer:

Plant A: y = 4x + 6

Plant B: y = 2x + 10

Otras preguntas