In the circle below, P is the center. If < APB measures 56 °, find the measure of < ACB.

Given the shown figure
since
The Central Angle Is Twice The Inscribed Angle
where
a= mACB
2a = mAPB=56
then
[tex]2a=56[/tex][tex]a=\frac{56}{2}[/tex][tex]a=28[/tex]a= mACB=28
Correct answer
option b
28