In order to calculate the change in volume, we can use the relation below:
[tex]\frac{P_iV_i}{T_i}=\frac{P_fV_f}{T_f}[/tex]If the pressure remains the same and the temperature increases by 2.53x, we have:
[tex]\begin{gathered} \frac{P\cdot V_i}{T}=\frac{P\cdot V_f}{2.53T}\\ \\ V_i=\frac{V_f}{2.53}\\ \\ V_f=2.53V_i \end{gathered}[/tex]Therefore the volume also changes by a factor of 2.53.
