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ANSWER
The volume of ammonia gas is 169.3L
EXPLANATION
Given that
The pressure of the gas is 244 torr
The temperature of the gas is 35 degrees Celcius
The mass of HCl is 235g
Follow the steps below to find the volume of the ammonia gas.
Step 1; Write the balanced equation of the reaction
[tex]\text{ 2NH}_{3(g)}\text{ + 3Cl}_{2(g)}\text{ }\rightarrow\text{ N}_{2(g)}\text{ + 6HCl}_{(g)}[/tex]In the above reaction, 2 moles Ammonia react with 3 moles Cl2 to give 1 mole N2 and 6 moles HCl
Step 2; Find the number of moles of HCl using the below formula
[tex]\text{ mole }=\text{ }\frac{\text{ mass}}{\text{ molar mass}}[/tex]Recall, that the molar mass of HCl is 36.458 g/mol
[tex]\begin{gathered} \text{ mole }=\text{ }\frac{235}{36.458} \\ \text{ mole = 6.45 moles} \end{gathered}[/tex]Step 3; Find the mole of NH3 using stoichiometry ratio
Recall, 2 moles NH3 give 6 moles HCl
Let x represents the number of moles of NH3
[tex]\begin{gathered} \text{ 2 mole NH}_3\text{ }\rightarrow\text{ 6 mole HCl} \\ \text{ x mole NH}_3\text{ }\rightarrow\text{ 6.45 mole HCl} \\ \text{ cross multiply} \\ \text{ 2 mole NH}_3\text{ }\times\text{ 6.45 mole HCl }=\text{ x mole NH}_3\times\text{ 6 mole HCl} \\ \text{ Isolate x} \\ \text{ x = }\frac{\text{ 2 mole NH}_3\times6.45mole\cancel{HCl}}{6mole\cancel{HCl}} \\ \\ \text{ x = }\frac{2\text{ }\times\text{ 6.45}}{6} \\ \text{ x = }\frac{12.9}{6} \\ \text{ x = 2.15 moles} \end{gathered}[/tex]The number of moles of NH3 is 2.15 moles
Step 4; Find the volume of NH3 using the ideal gas equation
[tex]\text{ PV = nRT}[/tex]Recall that, 35 degrees Celcius = 308.15K
[tex]\begin{gathered} \text{ R = 62.363 L. torr. mol}^{-1}.\text{ K}^{-1} \\ \\ \text{ 244 }\times\text{ V }=\text{ 2.15 }\times\text{ 62.363}\times\text{ 308.15} \\ \text{ 244V = 41,316.89} \\ \text{ Divide both sides by 244} \\ \frac{\cancel{244}V}{\cancel{244}}\text{ = }\frac{41316.89}{244} \\ \text{ V = 169.3 L} \end{gathered}[/tex]Therefore, the volume of ammonia gas is 169.3L
