The given equation is,
[tex]-15+6z=-8z+13[/tex]The objective is to solve the value of z and check the solution.
[tex]\begin{gathered} -15+6z=-8z+13 \\ 6z+8z=13+15 \\ 14z=28 \\ z=\frac{28}{14} \\ z=2 \end{gathered}[/tex]Hence, the value of z is 2.
Let's check the solution by substituting the value of z in the given equation.
[tex]\begin{gathered} -15+6z=-8z+13 \\ -15+6(2)=-8(2)+13 \\ -15+12=-16+13 \\ -3=-3 \end{gathered}[/tex]Since, LHS=RHS.
Hence, the value of z is correct.
