The slope of the line that passes through the points (x1, y1) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Given that the line passes through (-2,3) and (0,2), then its slope is:
[tex]m=\frac{2-3}{0-(-2)}=-\frac{1}{2}[/tex]The slope-intercept form of a line is:
y = mx + b
where m is the slope and b is the y-intercept
Replacing the point (0, 2) and m = -1/2 into the general equation, we get:
2 = -1/2(0) + b
2 = b
Then, the equation of the line is:
y = -1/2x + 2
