Answer
476.16 g of oxygen atoms
Explanation
The reaction can be represented in equation as shown below:
O₂ + H₂ → H₂O₂
From the information given in the question and also from the equation;
1 mole of O₂ reacts with 1 mole of H₂
1 mole of O₂ = 31.998 g/mol
1 mole of H₂ = 2.016 g/mol
So it means;
(1 mol x 31.998 g/mol) = 31.998 g of O₂ reacts with (1 mol x 2.016 g/mol) = 2.016 g of H₂
Therefore, x g of O₂ will react with 30 g of H₂
To get x, cross multiply and divide both sides by 2.016 g of H₂
[tex]x=\frac{30\text{ }g\text{ }H₂}{2.016\text{ }g\text{ }H₂}\times31.998\text{ }g\text{ }O₂=476.16\text{ }g\text{ }O₂[/tex]Hence, 476.16 g of oxygen atoms is required to react completely with 30 g Of hydrogen atoms
