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For problems 13-15, complete the chart below and then use the chart to determine the image points.90"(x, y) -(4-22,4)180°(x, y) - 42270"|(x,y) → (1,2-diy)13) Rotate 90" about the origin14) Rotate 180º about the origin15) Rotate 270" about the originM(3, 6) ► M'V(-5, -3) - VA(5, 3) AN(5, 10) - N'W/2. 1) - W'

Respuesta :

Given a point (h,k), we can rotate it using the following formulas:

Rotate 90 degrees: (h,k) becomes (k,-h)

Rotate 180 degrees: (h,k) becomes (-h,-k)

Rotate 270 degrees: (h,k) becomes (k,-h)

In this case, we have (for the 90 degrees rotation):

[tex]M(3,6)\text{ }\Rightarrow M^{\prime}(6,-3)\text{ }[/tex]

For the 180 degrees rotation:

[tex]V(-5,-3)\Rightarrow V^{\prime}(5,3)[/tex]

And finally for the 270 degrees rotation:

[tex]A(5,3)\text{ }\Rightarrow A^{\prime}(3,-5)[/tex]

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