(a)For an algebra class, all students took a Unit 5 test. Their scores and the amount of hours they studied are contained in the graph belowa student. A trend line (line of best fit) is given.Time Spent Studying(Hours)a) For the trend line,what is the slope?b) For the trend line,what is the y-intercept?c) Create a slope-intercept equationfor the trend line:

aFor an algebra class all students took a Unit 5 test Their scores and the amount of hours they studied are contained in the graph belowa student A trend line l class=

Respuesta :

[tex]\begin{gathered} x_1=0,y_1=50,x_2=2,y_2=70 \\ a)\text{ }\Rightarrow m=\frac{70-50}{2-0}=10(slope) \\ b)y-50=10(x-0) \\ y-50=10x \\ y=10x+50 \\ Y-\text{intercept is}\Rightarrow50 \\ c)y=10x+50(\text{slope}-\text{intercept equation)} \end{gathered}[/tex]