Respuesta :

Given:

[tex]\begin{gathered} f(x)=\sqrt[]{5x}+\sqrt[]{8} \\ x=2 \end{gathered}[/tex]

Derivative of function is:

[tex]\begin{gathered} f(x)=\sqrt[]{5x}+\sqrt[]{8} \\ f^{\prime}(x)=\sqrt[]{5}(\frac{1}{2\sqrt[]{x}})+\sqrt[]{8} \\ f^{\prime}(x)=\frac{\sqrt[]{5}}{2\sqrt[]{x}}+\sqrt[]{8} \end{gathered}[/tex]

At x=2 then the derivative is:

[tex]undefined[/tex]