Given that the initial velocity is
[tex]\begin{gathered} V_o=\text{ 2.7 km/h} \\ =2.7\times\frac{5}{18} \\ =0.75\text{ m/s} \end{gathered}[/tex]
The acceleration is a = 0.40 m/s^2
The time is t = 3.6 s.
We have to find the final velocity, v.
The final velocity can be calculated by the formula
[tex]V_f=V_o+at[/tex]
Substituting the values, the final velocity will be
[tex]\begin{gathered} V_f=0.75+0.40\times3.6 \\ =2.19\text{ m/s} \end{gathered}[/tex]
Thus, the final velocity is 2.19 m/s.
