Respuesta :

h(x) =

[tex]h(x)=\frac{2}{(x-4)^3}[/tex]

Let f(x) =

[tex]f(x)=\frac{2}{x^3}[/tex]

And

[tex]g(x)=(x-4)[/tex]

Then h(x) = f(g(x)) =

[tex]h(x)=\frac{2}{(x-4)^3}[/tex]