Answer:
[tex]y+3=0.8(x+2)[/tex]
Explanation:
Given that:
Slope of the line, m = 0.8
Point on the line = (-2, -3)
The point slope form of a line with slope m and passing through (a, b) is
[tex]y-b=m(x-a)[/tex]
Substitute the given values into the formula.
[tex]\begin{gathered} y-(-3)=0.8(x-(-2)) \\ y+3=0.8(x+2) \end{gathered}[/tex]
which is the required equation of line.
