We have to find the line that pass through this two points (2, 13) and (5, 22).
First, we can calculate the slope as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{22-13}{5-2}=\frac{9}{3}=3[/tex]Then, we can write the slope-point form of the equation using any of the two points and the slope and rearrange:
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-13=3(x-2) \\ y=3x-3\cdot2+13 \\ y=3x-6+13 \\ y=3x+7 \end{gathered}[/tex]Answer: y = 3x + 7 [Option C]
