Given:
The measure of the central angle O = 10
And the area of the circle = 20 square inches
We will find the area of the sector subtended by ∠O using the ratio and the proportional as follows:
Area of the circle : Area of the sector
20 A
360° 10°
Using the cross product, we will find the value of A
[tex]A=\frac{10*20}{360}=\frac{5}{9}\approx0.55555_-[/tex]
Rounding to the nearest tenth
So, the answer will be Area of the sector = 0.6 square inches
