Respuesta :

we need to reduce

[tex]\frac{-28x^2y}{7xy^2}[/tex]

this can be computed as

[tex](-\frac{28}{7})(\frac{x^2}{x})(\frac{y}{y^2})[/tex]

hence, we have

[tex](-4)(x)(\frac{1}{y})[/tex]

which is equal to

[tex]\frac{-4x}{y}[/tex]

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