Given the polynomial :
[tex]x^2-8x[/tex]To complete the square, we will add:
[tex](\frac{b}{2})^2[/tex]where b is the coefficient of x
b = -8
So, we will add:
[tex](\frac{b}{2})^2=(-\frac{8}{2})^2=(-4)^2=16[/tex]And the function will be:
[tex]x^2-8x+16=(x-4)^2[/tex]