We are given a matrix of
[tex]\begin{bmatrix}{4} & {3} & {0} \\ {-6} & {-3} & {12} \\ {} & {} & \end{bmatrix}[/tex]
Yasin performs R2 - 1/2R1
The second row and column will be
For the first row
-6 - 1/2(4)
-6 - 2
= -8
For the second row
-3 - 1/2(3)
= -3 -3/2
= -2 * 3 / 1 - 3 x 2 / 2 / 2
= -6 - 3 / 2
= -9/2
Third row
12 - 1/2(0)
= 12 - 0
12
The new matrix is
[tex]\begin{bmatrix}{4} & {3} & {0} \\ {-8} & {-\frac{9}{2}} & {12} \\ {} & {} & {}\end{bmatrix}[/tex]
