AlbertaG677846 AlbertaG677846

31-10-2022
Mathematics

contestada

Josiah measured a line to be 18.4 inches long. If the actual length of the line is 19.2
inches, then what was the percent error of the measurement, to the nearest tenth of a
percent?

Respuesta :

LeylandY78327 LeylandY78327

31-10-2022

Given:

The actual measurement is 19.2 inches.

The new measurement is 18.4 inches.

To find the percent error:

So, the formula is,

[tex]\begin{gathered} \frac{Actual-New}{\text{Actual}}\times100=\frac{19.2-18.4}{19.2}\times100 \\ =\frac{0.8}{19.2}\times100 \\ =\frac{80}{19.2} \\ =4.166667 \\ \approx4.2 \end{gathered}[/tex]

Hence, the percent error is 4.2%.

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