Given the net of a triangular pyramid:
As shown: all the triangles are equilateral triangles
The length of the side of the triangle = 7 ft
The height of the triangle = 6.06 ft
so, the area of one triangle =
[tex]\frac{1}{2}\cdot\text{base}\cdot\text{height}=\frac{1}{2}\cdot7\cdot6.06=21.21ft^2[/tex]
The pyramid consists of 4 triangles
So, the surface area =
[tex]4\cdot21.21=84.84ft^2[/tex]
so, the answer will be A = 84.84 ft^2
