If 0° ≤ A ≤ 180°, find ∠A, to the nearest tenth of a degree.

a) A = 140.6 degrees
b) A = 16.6 degrees
c) C = 122.9 degrees
d) C = 64.6 degrees
Explanation:[tex]\begin{gathered} \cos A=-0.7732 \\ \\ A=\cos^{-1}(-0.7732)=140.6^o \end{gathered}[/tex][tex]\begin{gathered} \sin A=0.2853 \\ \\ A=\sin^{-1}(0.2853)=16.6^o \end{gathered}[/tex][tex]\begin{gathered} \tan C=-1.5477 \\ \\ C=\tan^{-1}(-1.5477)=180-57.1327=122.9^o \end{gathered}[/tex][tex]\begin{gathered} \cos C=0.4288 \\ \\ C=\cos^{-1}(0.4288)=64.6^o \end{gathered}[/tex]