THe Mars rover can travle 4.9 cm in one second, so to finde the distance he made in 15/2 second we can made a tule of 3 so:
[tex]\begin{gathered} 4.9\to1 \\ x\to\frac{15}{2} \end{gathered}[/tex]and the expression will be:
[tex]x=\frac{4.9\cdot\frac{15}{2}}{1}[/tex]and we solve for x
[tex]\begin{gathered} x=4.9\cdot7.5 \\ x=36.75 \end{gathered}[/tex]So the solution will be that the Mars rover can travle 36.75 cm in 15/2 seconds
