chasingthreekids chasingthreekids

30-03-2017
Mathematics

contestada

Damon and Eddie each had an equal amount of money. Each day Damon spent $18 and Eddie spent $24. When Eddie used up all his money, Damon still had $120 left. How much money did each of hem have at first?

Respuesta :

30-03-2017

D = $18
E = $24
x - $18 = 120
x = $138

Answer Link

jducar35 jducar35

30-03-2017

$480 they each spent their amount for 20 days
damon 480- 18(20)= 120
eddie 480-24(20)= 0
hope this helped

Answer Link

Otras preguntas

T varies with the cube of w. When w is 3, T is 1/9.Find the value of w when T is 1/243.I don't understand any Variations!

Classify the following words into formal and informal english. 1.Commerce 2.What's up 3.May be 4.Thanks 5.Patrons 6.Banquet 7.Grant 8.Do you fancy 9.Engage 10.S

2x-3y=14 2x-y=-10 How you do this ?

An athlete with a high count of red blood cells will perform well in tests of physical endurance because (a) waste products will be removed from the body easily

which of the binomial below is a factor of this trinomial? 2x^3-18x^2+40xa) 2x+5b)x+5c)x-5d)2x-5

T varies with the cube of w. When w is 3, T is 1/9.Find the value of w when T is 1/243.I don't understand any Variations!

During a science experiment, Peter found the temperature of a certain liquid to be −a∘ Centigrade after he had raised the temperature by x degrees.Write an expr

which of the following is the the correct factorization of this trinomial. -3x^2-10x-8 a) (-3x+4)(x-2) b) -(x+4)(x-3) c)-(3x+4)(x+2) d) -3(x+4)(x+2)

1. x=1/(root3-root2). find rootx-(1/rootx) 2. if x=[root(a+2b)+root(a-2b)]/[root(a+2b)-root(a-2b]. show that bx^2-ax+b=0

1. x=1/(root3-root2). find rootx-(1/rootx) 2. if x=[root(a+2b)+root(a-2b)]/[root(a+2b)-root(a-2b]. show that bx^2-ax+b=0