alien666
alien666
27-05-2017
Mathematics
contestada
(y-7)(y+3)<(y-3)(y+3)
Respuesta :
tonb
tonb
27-05-2017
If you work out both sides, you get:
y^2 - 4y - 21 < y^2 - 9
-4y < 12
y > -3 (remember, if you divide by a negative number, the less-than flips and becomes a greater than)
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