A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m. What was its acceleration? (Unit = m/s^2)

Respuesta :

Torricelli's equation
Vf² = Vo² + 2aΔx

Vf = 10,9 m/s
Vo = 27,7 m/s
a = ?
Δx = 105

Therefore:

10,9² = 27,7² + 2*a*105

118,81 = 767,29 + 210a

210a = -648,48

a = -648,48 / 210

a = -3,088 m/s²