KarinaTM
KarinaTM
31-05-2017
Mathematics
contestada
Can someone help me with this please?
Respuesta :
bcalle
bcalle
31-05-2017
(2/3)^(1-1) + (2/3)^(2-1) + (2/3)^(3-1) + (2/3)^(4-1)=
(2/3)^0 + (2/3)^1 + (2/3)^2 + (2/3)^3=
1 + (2/3) + (4/9) + (8/27) =
(27/27) + (18/27) + (12/27) + (8/27) =
65/27 = 2 11/27
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