Respuesta :

WojtekR
[tex]x^2+3x+3+\dfrac{2x^2+13x+15}{x+5}=x^2+3x+3+\dfrac{2x^2+10x+3x+15}{x+5}=\\\\\\= x^2+3x+3+\dfrac{2x(x+5)+3(x+5)}{x+5}=\\\\\\=x^2+3x+3+\dfrac{(2x+3)(x+5)}{x+5}=x^2+3x+3+2x+3=\\\\\\=\boxed{x^2+5x+6}[/tex]

Answer B.